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Old 11-22-2005, 05:55 PM   #1 (permalink)
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Default physics question - pendulums

most of you will probably know that with a simple bob pendulum, in small amplitude swings,

T=2(pi)x√l/√g


this can be rearranged, calling 2 pi and g: k,"constant", as

T=kx√l (k=2.01)

or T(is proportional to)√l



What I want to know is WHY T is proportional to route l, rather than just l. Any help would be greatly appreciated.
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Old 11-22-2005, 05:58 PM   #2 (permalink)
 
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The answer is really quite easy.............assuming you're a physics major which I'm not....

Sorry, I never got up that high
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Old 11-23-2005, 02:36 AM   #3 (permalink)
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anyone else? i need to know this for my science coursework.
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Old 11-23-2005, 02:45 AM   #4 (permalink)
 
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Quote:
Originally posted by Nubius
The answer is really quite easy.............assuming you're a physics major which I'm not....

Sorry, I never got up that high
ROFL.

I'm gonna learn that next year, can't wait.

Yea, um, sorry, can't help either. But, try the Physics Forums. Some Quantum Physicists there .
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Old 11-23-2005, 10:07 AM   #5 (permalink)
 
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It's not directly proportional to I because of the power to 1/2, which is equivalent to the square root. Try doing the math. If you change the I by constant amounts, the T does not change my constant amounts. The square root matters because it is not a constant acting on the I, it is a power.

Hope that helps a little bit.
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Old 11-23-2005, 01:27 PM   #6 (permalink)
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thankyou for the link, Flanker

and thanks shenlingstyle.
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