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Old 04-08-2007, 06:48 PM   #1 (permalink)
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Default physics problem

Here a physics problem that came to my mind. If somebody thats just standing and he leaps into the air straight up and falls down to the same spot where he jumped, how high did he reach if the jumping and falling took .91 seconds?
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Old 04-08-2007, 07:14 PM   #2 (permalink)
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Default Re: physics problem

so assuming i did this right, he reaches a height of 1.01442m.

That assuming no wind resistance, earth's gravity, and ignoring earth's rotation (if he jumps straight up, he'll land at a different spot since earth is rotating).
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Old 04-08-2007, 07:33 PM   #3 (permalink)
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Default Re: physics problem

how did you get to that answer?
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Old 04-08-2007, 07:34 PM   #4 (permalink)
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Default Re: physics problem

is it right?
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Old 04-08-2007, 07:36 PM   #5 (permalink)
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Default Re: physics problem

its about 40 inches
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Old 04-08-2007, 07:45 PM   #6 (permalink)
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Default Re: physics problem

40in * .0254m/in = 1.01600m ~=1.01442m

it was pretty easy. (using metric units) we know that g = 9.8m/s^2 and we know that the time going up is the same as the time going down. So I just integrated twice to get displacement over half of the .91 seconds.

it all comes down to this:

a = dv/dt = d^2x/dt^2,

where a = acceleration v = velocity x = displacement
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Old 04-10-2007, 02:13 AM   #7 (permalink)
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Default Re: physics problem

seems right to me. peterhuang, why would you use anything but SI units for physics?
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Old 04-10-2007, 02:18 AM   #8 (permalink)
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Default Re: physics problem

It's also assuming his feet are always in exactly the same position relative to the rest of his body.

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Old 04-10-2007, 02:30 AM   #9 (permalink)
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Default Re: physics problem

yeah i noticed a few days ago but i've been too lazy to 'chop a new one
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Old 04-10-2007, 09:57 AM   #10 (permalink)
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peterhuang, why would you use anything but SI units for physics?
Homework lol.
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