[vernong1992]

This isn't even in the examples the book gives at the beginning but its in the homework part..

so I need an explanation..

Find a relationship between x and y so that (x,y) is equidistant from the two points (4,-1) and (-2, 3) in standard form.

Looking at the back the answer is 3x-2y-1 =0

I see what they did to get the slope (Midpoint formula, then changed it to it was perpendicular... but I don't get where the rest came from... that's where the help comes in and why that method is right)

[Peter.Cort]

what do you mean by the rest of it? that formula is standard from for a slope. Ax+By+C=0 in y=mx+b it would be y=3/2x-1/2

[El_Roberto]

You find the gradient using (y2-y1)/(x2-x1)=m
Then substitude the values into y-y1=m(x-x1)
then rearrange to the weird answer layout.

[Poizen22]

omg proff i didnt retain slope in school i thought it was the most pointless thing when learnign it here i am over a year later and i dont remeber a thing about it lol. meh im an artist math and english befoudns me.