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Old 01-14-2008, 07:16 PM   #11 (permalink)
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Default Re: Math help

Maths is such an easy thing to deal with :

[4^2+3^2 = x^2 => 25 = x^2 ==> X=5]
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Old 01-14-2008, 07:27 PM   #12 (permalink)
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Default Re: Math help

Math is so easy. I can't believe you are stuck on that problem. You should be able to do that in your head at 14.
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Old 01-14-2008, 09:51 PM   #13 (permalink)
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Default Re: Math help

I loved math.... was great at it till I hit college, and enrolled in the wrong honors math class..... opps.... had to MEMORIZE all the equations, and only could use a small little calc, no graphing calc. Oh well....

KMAN, are you familiar with PEMDAS? Thats what you use to solve for X....
(this is dumb, but it is a trick to try an remember it.... learned this about 12 or more years ago.....)
Please (Parenthesis)
Excuse (Exponents)
My (Multiplication)
Dear (Division)
Aunt (Addition)
Sally (Subtraction)

When working equations, you are supposed to work from left to right with PEMDAS, addition & subtraction being last.....
The "work" is shown in bracets [].

2x + 8 / 2 = 14

multiply both sides of the equation by 2......
[2x + 8 / 2 * 2 = 14 * 2]
2x + 8 = 28

then subtract 8
[2x + 8 - 8 = 28 - 8]
2x = 20

divide both sides of equation by 2
[2x / 2 = 20 / 2]
x = 10

Fairly simple.... do a few problems, and you'll get the hang of it.
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Old 01-14-2008, 09:57 PM   #14 (permalink)
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Default Re: Math help

Yes. All elementary math learns must remember PEMDAS. It will help you when you get to higher level math.
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Old 01-15-2008, 12:00 AM   #15 (permalink)
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Default Re: Math help

Quote:
Please (Parenthesis)
Excuse (Exponents)
My (Multiplication)
Dear (Division)
Aunt (Addition)
Sally (Subtraction)
over here we were taught basically the same thing but we called it BIMDAS (where B and I stand for Brackets and Indices respectively).

mssssee2 we actually had someone do that in an exam at my high school!
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Old 01-15-2008, 02:55 AM   #16 (permalink)
 
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Default Re: Math help

BIDMAS?

I've topped out at a level maths. Could someone help with this one.

cot 2θcosec2θ______
tan² θsec2θ + sec2θ = (cosθcot2θ)^n

and find n. Eek...
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Old 01-15-2008, 03:11 AM   #17 (permalink)
 
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Default Re: Math help

OK, should people still be replying to this thread? It appears the OP got banned.
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Old 01-15-2008, 04:49 AM   #18 (permalink)
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Default Re: Math help

Don't worry, he'll be back. It is a suspension, not a perm ban.
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Old 01-15-2008, 04:52 AM   #19 (permalink)
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Default Re: Math help

OT but why did kman get temp baned?
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Old 01-15-2008, 11:14 AM   #20 (permalink)
 
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Default Re: Math help

To the OP, Im 15 and i am doing my GCSE in like 3 months and i still dont have a clue... lol
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