[Static_11]

Alright.. this thread was inspired by my math problems thread.. I figured alot of people on here go to school so why not start a little homework help thread??
Alright.. well today we got a new thing in math.. a problem of the month thing thats do by next friday.

Problem:
There is a cube. Each side is 3 units. Each side is painted red. If the cube was split into 27 evenly size peices, how many peices would have red sides?

[brady]

Man, Im too old to think like that. Reading that made my brain take a nap.

[gimli of gloin]

wat a stupid question......i think the answer is one...if it is the cube in the very centre. im assuming by the sides being 3 units u mean 3x3.

EDIT: if the 27 peices didnt have to be exatly the same ( congruent) but just equal in volume then u could cut them in such a way as to make all of them hae a bit of red/

[Static_11]

no no no... the problem is you have a cube ok?

the problem just says that each side is 3 units.... idk wth that means.. length? idk..
anyway.. when it says put it in 27 equal parts it means to take that 1 cube and make 27 other cubes out of it.. think of it as a rubics cube....

[horndude]

if its 3x3 as in just like a rubiks cube, then all 27 cubes would have 1 red side

[gimli of gloin]

its not a rubix cube....its just a cube.

the very centre wouldnt have any red sides>>>

[Emily]

I say 26 will have at least one red side. Like gimli said, there's one cube in the center that doesn't touch the outside at all.

[Static_11]

thats what i was thinking.... ok.. anyone else?

[Chankama]

By red sides you mean "at least one side of the mini-cube is red", then yeah.. Obviously, it's 26 .. ASSUMING THE BIG CUBE IS CUT INTO SMALL CUBES!

This is assuming that the cube is divided into "mini cubes". It is also possible that the cut pieces are "not" cubes.. For example, 1/2 cubes cut across the diagonal. I am sure "this" is not the correct shape, but it is conceivable that you can "cut" the big cube into small pieces that are "not" mini-cubes. Into 27 of them. Some funky shape that we won't even imagine about.

Solving this would be involved. Equal volume pieces constrained by the border of the big cube.. Who knows how many solutions there are.

I just don't have the time... .. But yeah.. Keep it in mind..

[Chankama]

I am on drugs.. Why the **** was I thinking so complicated.. Just divide the **** cube into 27 rectangles.. Man, I need sleep..

Equal pieces.. All have red on them.. Same result.. Anyways, I think my previous "division" had problems with it anyways.. Forget there were 2 sides to the increasing process. But, yeah.. 27 rectangles with 1/27 thickness is definitely safe ..

===================================

Conclusion:
This question is a badly written question.