[KryptoKnight]

Ok.. I was making an age program, but came upon a problem... not too lifethreatening, but kind of weird. Here it is....

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
int age;

cout<<"Please input your age: ";
cin>> age;
cin.ignore();
if ( age < 100 ) {
cout<<"You are pretty young... Let's all point and laugh!\n";
}
else if ( age == 100 ) {
cout<<"You are old... let's all point and laugh!\n";
}
else {
cout<<"You are really old, Sensei!\n";
}
cin.get();
}

I can enter the usual (99, 100 , 10, 1000,) but if I go any higher, like a trillion, it doesn't work and just shuts off on pressing enter

[Emily]

The integer data type can only hold up to 37,000 or around there.

[crazybeans]

you may need to declare your variables differently. Here is some information on variable memory range values you can use for future problems like this one.

Note: on the left is the variable type, on the right is the maximum number alocated in memory for the variable type. I'll add the real number as well as the 2^n.

long long int = plus/minus 2^63 or 9223372036854775808
long int = plus/minus 2^31 or 2147483648
int = same as long int
short int = plus/minus 2^15 or 32768

if you ever try to add a number larger than the given range to a variable you will either "wrap" the number (go back to negative side and work your way up) or you will get a "floating point exception". Hope that helps. That information will cost you $1.00 and a Rodeo Cheeseburger

[furtivefelon]

not sure about c++ (i'm pretty sure they have some kind of arbitrary precision type for a variable?), but in c, if you need a very large of anything, you use malloc..

[Cache]

Originally posted by furtivefelon
not sure about c++ (i'm pretty sure they have some kind of arbitrary precision type for a variable?), but in c, if you need a very large of anything, you use malloc..

The C++ equivalent of malloc is new.

Typical usage (much nicer than malloc ):

char* pszText = new char[0xff];