[cleverest]

Please someone help me, I'm supposed to come up with a C++ code to give the following dialog (user input capable text is in BOLD) I'm supposed to have one loop for full credit... but I'm not even concerned with that if I'm able to make this work some other way....what I have done so far is below and it's driving me nuts (I told you...I'm a total newbie!) :-D

I only have till midnight today!! Please someone help me out, I'll study it an learn it better then fighting with it all day and failing the challenge

(with the understanding that during
boom times, population increases by 15%. During bad times,
population decreases by 20%)

This is the desired dialog when the program is Run:

Enter a starting population size: 1000
After a boom year, your population has grown to:1150
After a bad year, your population has shrunk to:800
Continue(y/n)? y
Was it a boom or bad year (o/a)? o

Your starting population is now 1150
After a boom year, your population has grown to:1323
After a bad year, your population has shrunk to:920
Continue(y/n)? y
Was it a boom or bad year (o/a)? a

Your population is now 920
After a boom year, your population has grown to:1058
After a bad year, your population has shrunk to:736
Continue(y/n)? n
Was it a boom or bad year (o/a)? o

Your final population is 1058

#include <iostream>
using namespace std;


int main()
{
	double population = 0;
	double boom_year;
	double bad_year;
	char contin;
	char boomornot;

	cout << "Enter a starting population size: ";
	cin >> population;
	boom_year = (population * 1.15);
	bad_year = (population * 0.8);
	cout << "After a boom year, your population has grown to: " << boom_year << "\n";
	cout << "After a bad year, your population has shrunk to: " << bad_year << "\n";
	cout << "Continue(y/n)? "; // determines which IF statement below to acccess
	cin >> contin;

	if (contin == 'n') // I'm pretty confident with this section, it displays final result and then exits
	{
		cout << "Was it a boom or BAD year (o/a)? ";
		cin >> boomornot;
		if (boomornot == 'o')
	    {
		population = boom_year;
		cout << "Your final population is " << boom_year << "\n";
	    }
			if (boomornot == 'a')
	        {
		population = bad_year;
		cout << "Your final population is " << bad_year << "\n"; 
	        }
	
	}


	if (contin == 'y') // this section is a mess...it works, but can't loop and can't figure it out otherwise...HELP!
	{
		cout << "Was it a BOOM or bad year (o/a)? ";
		cin >> boomornot;
		if (boomornot == 'o')
	    {
		population = boom_year;
		cout << "Your starting population is now " << boom_year << "\n";
	    }
			if (boomornot == 'a')
	        {
		population = bad_year;
		cout << "Your starting population is now " << bad_year << "\n"; 
	        }
	
	}


	// need more code probably....can someone brilliant help me out??
	


	return 0;
}

[Emily]

I don't have time to write out the whole program but you need to use a while loop. First, in the beginning, ask for a starting size, display boom year, display bad year, and then ask whether to continue. Now the while loop starts, with the condition while contin == 'y'. In the body of the while loop, you need to ask if it was a boom or bad year, display the appropriate starting population, display boom year, display bad year, and ask whether the user wants to continue.

After the body of the loop is where you put the code to handle a 'n' for continue, since execution will stay in the body until the user enters n. So after the closing bracket for the while loop is where you would put the code that you have for if contin == 'n' (and you don't need an if statement anymore).

Hope this helped.

[cleverest]

Actually I believe this will be VERY helpful, I'm going to try to work on what you said....

Since I've typed that sentence above this one, I've managed to write this code, and its VERY CLOSE...any suggestions anyone, to get it to resemble the program dialog in my first post up top?

#include <iostream>
using namespace std;

int main()
{
double population = 0;
	double boom_year;
	double bad_year;
	char contin;
	char boomornot;

	cout << "Enter a starting population size: ";
	cin >> population;
	boom_year = (population * 1.15);
	bad_year = (population * 0.8);
	cout << "After a boom year, your population has grown to: " << boom_year << "\n";
	cout << "After a bad year, your population has shrunk to: " << bad_year << "\n";
	cout << "Continue(y/n)? "; 
	cin >> contin;

	while (contin == 'y')
	{
    cout << "Was it a BOOM or bad year (o/a)? ";
		cin >> boomornot;
		if (boomornot == 'o')
	    {
		population = boom_year;
		cout << "Your starting population has grown to " << boom_year << "\n";
	    }
			if (boomornot == 'a')
	        {
		population = bad_year;
		cout << "Your starting population has shrunk to " << bad_year << "\n"; 
	        }
	cout << "Continue(y/n)? "; 
	cin >> contin;
	}

	 if (contin == 'n') 
		cout << "Was it a boom or BAD year (o/a)? ";
		cin >> boomornot;
		if (boomornot == 'o')
		{
		population = boom_year;
		cout << "Your final population is " << boom_year << "\n";
		}
	    


}

Also the program dialog that exists with the above program I've written is as follows and it doesn't match the goal exactly which is shown in the first post.....can anyone help? (I'm such a newbie but I'm learning!)

Enter a starting population size: 1000
After a boom year, your population has grown to: 1150
After a bad year, your population has shrunk to: 800
Continue(y/n)? y
Was it a BOOM or bad year (o/a)? o
Your starting population has grown to 1150
Continue(y/n)? y
Was it a BOOM or bad year (o/a)? a
Your starting population has shrunk to 800
Continue(y/n)? n
Was it a boom or BAD year (o/a)? o
Your final population is 1150
Press any key to continue

[Emily]

At the beginning of your while loop you need to display the present population (The starting population is now... ), calculate a boom and a bad year and display both the values (After a boom year... after a bad year...).