[simple]

i want to implement a C program where the program will run for 1 minute and then terminate itself. I can monitor how much time my program has run but i cannot implement a timer for the same program.
any help is sincerely appreciated. thanks and c ya!!

[simple]

apparently no one has any solution????

[Baez]

#include<conio.h>
#include<time.h>

int main()
{
   while(!kbhit()) /* this function might use a different header file for you depending on your compiler */
   {
       sleep(60000); /* counts in milliseconds, this is one minute */
   }
}

I think this is what you want. Let me know . Any reason you're using C and not C++? Haven't learned object orientation yet?

[simple]

can't use conio.h because i am using gcc compiler on linux platform.
and i have to use C . its a small thing and i dont have any issues with object oriented stuff.
thanks for your time...hope i get some relevant replies!!
c ya!!

[void]

Have a look at the system call getrusage(). If you use RUSAGE_SELF as the first parameter then the rusage struct is filled with process information about the current process. Then you need to process the timeval structures ru_utime and ru_stime. Each of these contain the user and system time used by the process. For example this prints the CPU time:

#include <stdio.h>
#include <sys/time.h>
#include <sys/resource.h>
#include <unistd.h>

int main(int argc, char *argv[]) {
	struct rusage process_usage;
	getrusage(RUSAGE_SELF, &process_usage);
	printf("CPU time: %ld.%06ld sec user, %ld.%06ld sec system\n", 
		process_usage.ru_utime.tv_sec, process_usage.ru_utime.tv_usec, 
		process_usage.ru_stime.tv_sec, process_usage.ru_stime.tv_usec
}

Also have a look at alarm(). This will raise a SIGALRM which use can handled by setting a function to be called using signal().

If you have the manual pages installed you can find out more with the command:

man [function name]

Finally I highly recommend the free book Advanced Linux Programming. It details many of the techniques used to solve problems like the one you mentioned. It quite a read but its worth it.

Edit: Heres a sample program that will run for a minute and print CPU time at the end.

#include <signal.h>
#include <stdio.h>
#include <sys/time.h>
#include <sys/resource.h>
#include <unistd.h>

void timer_expired(int signal);

sig_atomic_t active;

int main(int argc, char *argv[]) {
	signal(SIGALRM, &timer_expired);
	//Sets the alarm to raise a SIGALRM in 60 seconds.
	alarm(60);
	active = 1;
	fprintf(stdout, "Running ");
	while (active) {
		printf(".");
		fflush(stdout);
		sleep(1);
	}
	printf("\n");
	struct rusage usage;
	if (getrusage(RUSAGE_SELF, &usage) == -1) {
		printf("Failed to get usage information.\n");
		return 0;
	}
	printf("CPU time: %ld.%06ld sec user, %ld.%06ld sec system\n",
			usage.ru_utime.tv_sec, usage.ru_utime.tv_usec,
			usage.ru_utime.tv_sec, usage.ru_utime.tv_usec);
	return 0;
}

[mattew]

well its got much a simpler solution i beleive ..
u can use the delay function which comes under dos.h or proces.h got a doubt about that...
well using the delay function and later on exit the program using exit (0);
or abort();
will do ur job

*abort will not save ne data while program is in excecution and it will directly abort from it .. exit is a safer one to use *