PHP Problem

Arbitus · 01-26-2006, 02:23 AM

Well I decided to start again on PHP, I got destracted from the book to make a game I thought I could. I've got a lot done but I'm sort of stuck on something. It's a guessing game, where the user guess's a random number using rand(1,100). But when I decided to show the answer to test it, I found out that my random number, which I put in a variable, continues to change. Also, I had it working before, but it seems to not be working now, but when the number is guessed correctly, the congrats text in $win is not printed out. Here is the whole script. It's sloppy I know

Quote:

<html>
<head>
<title>
Guessing Game
</title>
<?php

// Define the variables
$random = rand(1,100);
$user = $_POST['yourguess'];
$highlow = " ";
$win = " ";

if ($user > $random)
{
$highlow = "Lower";
}
else if ($user < $random)
{
$highlow = "Higher";
}
else if ($user == $random)
{
$highlow = "Winner!";
$win = "Congradulations, you won!";
$random = rand(1,100);
}
else
{
$highlow = "s ";
}

?>
</head>
<Body bgcolor="#558BB7" text="#000000">

<center>
<h1>
<?php
echo "$win";
?>
<form method="POST" action="random.php">
<table border="1" width="56%">
<tr>
<td width="47%">
<p align="center">Your Guess:</td>
<td width="53%"><input type="text" name="yourguess" size="20"></td>
</tr>
<tr>
<td width="47%">
<p align="center">Higher or Lower:</td>
<td width="53%">
<?php
echo $highlow;
?>

</td>
</tr>
<tr>
<td width="53%">
<p align="center">Answer:</td>
<td width="53%">
<?php
echo $random;
?>

</td>
</tr>
<tr>
<td width="47%">
<p align="center">Give Up?:</td>
<td width="53%">
<p align="center">
Yes: <INPUT type="checkbox" name="giveup" value="OFF"
</td>
</tr>
<tr>
<td colspan="2">
<p align="center"><input type="submit" value="Guess!"></td>
</tr>
</table>

</form>

</center>

</body>
</html>

Also, how can I make it so the textbox doesn't show old answers. I don't like how it auto-completes like that.

If you don't understand what I'm talking about for either of my questions. You can see that script here: www.arbitus.jaysworldnetworks.com/PHP/random.php

TheHeadFL · 01-26-2006, 05:49 AM

Simple fix on your main problem:

You need to add an input type "hidden" to your script, and the value of this would be the random number you calculated.

Therefore, at the beginning of the script, if the hidden input is not null, you generate a new random. Otherwise, treat that as your previously decided random value.

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