[cloud]

I have an assignment to write a program in C that does the following:



Write a C program that will accept a 3-digit positive integer 0 to 999.
The program will determine that it is a valid number in this range and
terminate if not. If valid, the program will compute the square of the
number. Then the program will reverse the digits of the number so that 395 become 593 and 37 becomes 73. Print out the number, the square and the reversed digit number. Example: if 250 is entered, then it will print: 250, 62500, and 052.


I'm not that good with C, so any suggestions would help

[Pavlyk]

Perhaps a manual would help you?

[cloud]

Yeah, is there anywhere with good C tutorials?

[billgrande]

http://www.strath.ac.uk/IT/Docs/Ccourse/ would be your best bet for info on C.

as far as the program goes try something like this for the main function of your program.

main()
{
//declare your variables and get the number from user

if(num >=0 && num <=999)
{

//your code here

}
else
exit(0);
}

[cloud]

That is really helpful, thanks a lot.

[intercodes]

cloud,


Note: I didnt compile the program,there maybe errors with the variables


#include <stdio.h>
int main(void)
{
long int number,square,reverse=0,temp,rev1=0;
printf ("Enter the number: ");
scanf("%li",&number);
if( number >=0 && number <=999)
{
square = number*number;
while(number>0)
{
temp=number%10;
rev1=reverse*10;
reverse=rev1 + temp;
number/=10;
}
printf("\n The input number is : %li" ,number);
printf("\n The square of the number is : %li",square);
printf("\n The reverse of the number is : %li",reverse);
}
return 0;
}

[cloud]

Wow thanks a lot, it works great, only it returns the input is 0, but i can fix that, thanks a lot codes.

[intercodes]

cloud,

Oh yeah, i forgot to use the original value...oopzz! .Hope you got it.

[cloud]

Yeah i got it, thanks a lot for all your help, with both programs.