[Vormund]

I'm trying to make a simple batch file for compiling Java files via the command line, for the time being to do this:

1. Run the batch.
myBatchFile.bat MyClass

2. Compile the file.
javac %1.java

3. Determine if an error was spewed by Java, if so, abort, otherwise continue.
This is where the problem is - how to determine if Java spewed an error.

I was thinking along the lines of running the compile command with the > file.txt, and determining if file.txt had content, if so, there was an error...but that doesn't work, it only creates an empty file (which I don't fully understand as of yet).

As well, I still want the error displayed on the screen, so even if it did work, I want the error displayed as well.

4. Run the class
java %1


The bottom line, does anyone have any idea how to do #3? If you need clarification, let me know...

TIA!
Vormund

[jaeusm]

You could take a slightly different approach. Instead of trying to redirect the compiler output to file, just check to see if a .class file exists. Of course, this method would require you to first check the directory for an existing .class file and delete it before calling javac.exe.

[Vormund]

Originally posted by jaeusm
You could take a slightly different approach. Instead of trying to redirect the compiler output to file, just check to see if a .class file exists. Of course, this method would require you to first check the directory for an existing .class file and delete it before calling javac.exe.

Hah, that's perfect...and solves both issues!

Thanks, jaeusm!

[jaeusm]

You're welcome. A better solution might be to use the return code from javac.exe. However, I don't know how to obtain the code for use in a batch file. You'd have to do some research for that.