[SkyHi]

We literally started C++ 2 days ago, and my teacher knows nothing, we're supposed to do this program:

Write code that will multiply some number by 2 if the number is between 1 and 100 (including 1 or 100) and if it is evenly divisible by 3; otherwise multiply by 3 if it is between 1 and 100 but not divisible by 3; finally, if it isnÂ’t between 1 and 100, multiply the number by the number modulus 100. Hint: Use the nested if statement

Can anyone give me some starters? I know the basics, but how do you see if it's divisble by 3?? I can do it but it'd take like 15+ lines of code, is there a simple way?
ANY help is appreciated!

[Emily]

You have to use an if else if else statement. To see if a number is divisible by 3, use the modulus operator (%). That returns the remainder, so if the remainder is 0, it is divisible by 3.

if ((n>=1) and (n<=100) and (n%3 == 0)) {
n*=2;
} else if ((n>=1) and (n<=100)) {
n*=3;
} else {
n = n * (n%100);
}

Hope this helped.

[SkyHi]

Thanks, but not really cuz I can't have it tell you modulus and THEN go on thanks though!!

[Emily]

What do you mean?

[SkyHi]

Emily, sorry about that, that works fine, Thanks.

[M4A1]

Yeah, it can seem confusing at times. The modulus operator basically tells you if x is divisble by y, it is only if it has no remainders. (x % y == 0) means that it is equally divisible. Have fun with C++, it's a great programming language.