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santechz · 03-21-2005, 12:01 PM

this is how i visualize my question

char * p1 = (char*)malloc(sizeof(char)); //sizeof(char)=1 byte
char * p2 = (char*)malloc(sizeof(char));

now i get p1 = 1460
then p2 must be 1461 (or 1462 for adjustment) if there were no allocation to heap in between these two statements, bcoz this would be the easiest to implement the heap management....

but i get p2 = 1468. in other words, there are 7 bytes which I believe I can use. Why did malloc return 1468 and not 1461(/1462)? Can i really use these 7 bytes. will the heaper (?) allocate these 7 bytes (even when i havent freed p1 and p2) when i request a ..say malloc(4 * sizeof(char))?

regards

03-21-2005, 12:01 PM	#3 (permalink)
santechz Newb Techie Join Date: Mar 2005 Posts: 3	this is how i visualize my question char * p1 = (char)malloc(sizeof(char)); //sizeof(char)=1 byte char p2 = (char)malloc(sizeof(char)); now i get p1 = 1460 then p2 must be 1461 (or 1462 for adjustment) if there were no allocation to heap in between these two statements, bcoz this would be the easiest to implement the heap management.... but i get p2 = 1468. in other words, there are 7 bytes which I believe I can use. Why did malloc return 1468 and not 1461(/1462)? Can i really use these 7 bytes. will the heaper (?) allocate these 7 bytes (even when i havent freed p1 and p2) when i request a ..say malloc(4 sizeof(char))? regards