Quote:
Originally Posted by S0ULphIRE  Regex pattern = new Regex("[0-9][0-9]{2}.[0-9][0-9]{2}.[0-9][0-9]{2}.[0-9][0-9]{2}"); try that. edit: this might be easier: Regex pattern = new Regex("[\d][\d]{0,2}.[\d][\d]{0,2}.[\d][\d]{0,2}.[\d][\d]{0,2}"); C# and Regex |
Your code didn't work. Firstly I was required to use three numbers in each octet. I want it to accept only 1-3 numbers. I fixed that by changing {2} to {1,3}. Then I could only put two or three numbers in, one number didn't match because you put [0-9] twice. I made it so it was was like [0-9]{1,3}, but that gets me back to the same code I already messed with earlier and I don't get the results I want.
Quote:
Originally Posted by kmote I also hate regex but in theory something like this might work
\d{1,3}(\.\d{1,3}){3}
this should look for 0-9 between 1 and 3 times then a dot followed by 1-3 numbers 3 times. In practise limited repetition ({1,3} etc.) is not always supported and you may be forced to use + instead. Occasionally \d isn't supported either in which case you can replace it with [0-9].
Filled with hate |
Your code also didn't work. The \d and \. didn't agree with it, so I made those [0-9] and . respectively. It worked, however, as long as three numbers are present I can add as many letters as I want.
For example, this matches: 1a1a1.2b2b2.3c3c3.4d4d4
I tried to fix it with this: [0-9]{1,3}[^A-Za-z](.[0-9]{1,3}){3}
But that doesn't help at all. Why?